Lecture
The addition theorem for probabilities of incompatible events
Theorem. Probability of the sum of a finite number of incompatible events equal to the sum of the probabilities of these events (2.1)
Evidence. Let us prove this theorem for the case of the sum of two incompatible events. and . Let the event favor elementary outcomes, and event A2: m2 outcomes. Since the events and according to the condition of the theorem, incompatible, then the A1 + A2 event is favored by m1 + m2 of elementary outcomes from the total number of n outcomes. Consequently, ,
Where - probability of an event ; - probability of an event .
An example . For shipment from the warehouse can be allocated one of two machines of various types. Known probabilities of highlighting each machine: .
Then the probability of receipt to the warehouse of at least one of these machines will be
P (A 1 + A 2 ) = 0.2 + 0.4 = 0.6.
In many cases, the probabilities of occurrence of some events depend on whether another event has occurred or not. For example, the probability of timely release of the machine depends on the delivery of components. If these products are already delivered, then the desired probability will be one. If it is determined before the delivery of components, then its value will obviously be different. Event probability calculated on condition that another event has occurred is called the conditional probability of an event and is denoted by . In cases where the probability of an event considered on condition that two other events occur , use conditional probability relative to the product of events .
Theorem. The probability of the product of two events is equal to the product of the probability of one of them by the conditional probability of the other, calculated under the condition that the first took place
P (AB) = P (A) × P (B / A) = P (B) × P (A / B ). (2.2)
Evidence. Suppose that all sorts of elementary outcomes event favor outcomes from which outcomes favor the event . Then the probability of an event will be conditional probability of an event regarding the event will be .
The product of events and only those outcomes favor the event. and event simultaneously, i.e. outcomes. Therefore, the probability of an event and equals .
Multiply the numerator and denominator of this fraction by .
Will get . The formula is proved similarly. .
An example . 35 refrigerators arrived at the warehouse. It is known that 5 refrigerators with defects, but it is unknown what kind of refrigerators it is. Find the probability that two randomly selected coolers will be defective.
Decision. The probability that the first refrigerator selected will be defective is found as the ratio of the number of favorable outcomes to the total number of possible outcomes P (A) = 5/35 = 1/7 . But after the first defective refrigerator was taken, the conditional probability that the second will be defective is determined based on the ratio
The desired probability will be .
If at the occurrence of the event event probability does not change, then the events and are called independent . In the case of independent events, the probability of their product is equal to the product of the probabilities of these events.
P (AB) = P (A) × P (B) . (2.3)
The probability multiplication theorem is easily generalized to any finite number of events.
Theorem. The probability of the product of a finite number of events is equal to the product of their conditional probabilities relative to the product of the preceding events, i.e. P (ABC .... LM) = P (A) × P (B / A) × P (C / AB) P (M / AB ... L) . (2.4)
To prove this theorem one can use the method of mathematical induction.
Two events are called joint , if the appearance of one of them does not exclude the appearance of the other in the same experience. Example. Admission to the store one type of product - the event . Receipt of the second type of product - event . These goods can be received simultaneously. therefore and - joint events.
Theorem. The probability of occurrence of at least one of two joint events is equal to the sum of the probabilities of these events without the probability of their joint occurrence P (A + B) = P (A) + P (B) - P (AB) . (2.5)
Evidence. Event A + B occurs if one of three incompatible events occurs. , , . By the addition theorem of probabilities of incompatible events, we have (2.6)
Event will happen if one of two incompatible events occurs: , .
Again applying the addition theorem for probabilities of incompatible events, we obtain .
From where
(2.7)
Similarly for an event
From where . (2.8)
Substituting (2.7) and (2.8) into (2.6), we find
P (A + B) = P (A) + P (B) - P (AB) .
Example. If the probability of entry into the store of one type of product is P (A) = 0.4,
and the second commodity, P (B) = 0.5, and if we assume that these events are independent, but are joint, then the probability of the sum of events is
P (A + B) = 0.4 + 0.5 - 0.4 × 0.5 = 0.7 .
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Probability theory. Mathematical Statistics and Stochastic Analysis
Terms: Probability theory. Mathematical Statistics and Stochastic Analysis