Determine the capacitance value of the capacitor at which the resonance of currents is possible. Build a vector diagram.
Given:

R1 = 40 Ohm
R2 = 10 ohm
f = 50 Hz

Decision:

Current resonance condition:

Determine the value of the conductances of the branches:

Solving a quadratic equation, we get two positive roots with values
reactive resistance Xc1 = 78.7; Xc2 = 1.25 ohm
choose one value Xc2 = 1.25 ohm and calculate the current:

Construction of the vector diagram

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Electrical Engineering, Circuit design
Terms: Electrical Engineering, Circuit design