Task 1
Determine the capacitance of the capacitor, if its resistance at the third harmonic is 500 Ohms.
Decision:
capacitor resistance XС = 1 / 3ɷС = 500 Ohm
C = 1 / XC ∙ 3ɷ = 1/500 ∙ 3 ∙ 314 = 2, 12 μF
Task 2
Determine the resistance of the coil, at the signal with the fifth harmonic, if the first harmonic
XL = 5 ohms.
XL5 = 5 ∙ ɷ ∙ L = 25 Ohm
Task 3
Determine the distortion factor and harmonic coefficient, if a signal is input to the device:
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Solution: calculate the effective value of the source voltage
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U1 = 0
CI = U1 / U = 0
Harmonic factor KG = Ug / U
harmonics actual value
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KG = Ug / U = 104, 4 / 106.3 = 0.928
Task 4
Determine the values: U1, I2
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Given:
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The calculation is carried out by the method of superposition (superposition).
1. Calculation of the constant component of U = 20 B
The scheme takes the form
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2. First harmonic calculation
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Decision
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4 branches, two knots
You can solve any method: equivalent transformations, two nodes
Solve the method of equivalent transformations.
Find the equivalent resistance:
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The effective value of the input voltage:
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Complex stress
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Determine the current source:
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Determine the voltage between the nodes "av"
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Effective voltage value:
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Determine the currents in the branches:
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Rated current:
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Rated current:
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Rated current:
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3. Calculation of the second harmonic
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Complex stress
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Decision
4 branches, two knots
You can solve any method: equivalent transformations, two nodes
Recalculation of reactance values
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The effective value of the input voltage:
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Determine the current source:
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Determine the voltage between the nodes "av"
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Effective voltage value:
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Determine the currents in the branches:
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Rated current:
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Rated current:
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Rated current:
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4. Final calculations. We determine the total effective values:
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Electrical Engineering, Circuit design
Terms: Electrical Engineering, Circuit design