Lecture
| Consider an example of constructing plots of transverse forces Q and bending moments M x |
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| Fig. 5.2 (a, b) |
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| Since the reaction of R B with a minus, we change the chosen direction to the opposite (Fig. 5 2,6). |
| Check: |
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| The values of the reactions found are shown in Fig. 5.2 b. |
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| The origin of coordinates is chosen at the leftmost point O 1 . Consider the equilibrium of the cut-off part of the beam (Fig. 5.3). |
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| Fig. 5.3 |
| Internal forces arise in the section: |
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| Section II O 2 B; |
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| The origin of the coordinates is transferred to the beginning of the O 2 segment (Fig. 5.4). |
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| Fig. 5.4 |
| On the 2nd segment in the moment equation, the arguments (Z 2 ) have the 2nd degree, which means that the plot will be crooked of the second order, i.e. parabola. |
| In the second section, the transverse force changes sign (the beginning of the section + ga, and at the end -ga), then on the plot M x there will be an extremum at the point where Q = 0. Determine the coordinate of the section in which the value M x is extreme, equating the expression of transverse force on this site is zero. |
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| Determine the magnitude of the extreme moment: |
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| Section III VO 3 . |
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| The origin of coordinates in the third section is placed at the rightmost point of O 3 (Fig. 5.5). |
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| Fig. 5.5 |
| Here |
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| Fig. 5.6 |
| 6. Check the correctness of plotting. |

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Strength of materials
Terms: Strength of materials