Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vieta's Theorem

Lecture 23 min.



A quadratic equation is an algebraic equation of the general form

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

where Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem is the unknown, Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem are coefficients, and Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

The expression Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem is called a quadratic trinomial .

A root is a value of the variable Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem that turns the quadratic trinomial into zero, and the quadratic equation into a true numerical equality.

The elements of a quadratic equation have their own names :

  • Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem is called the first or leading coefficient,
  • Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem is called the second or middle coefficient, or the coefficient of Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem,
  • Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem is called the constant term.

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

A quadratic equation whose leading coefficient equals one is called reduced (or monic) . Such an equation can be obtained by dividing the whole expression by the leading coefficient Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

A quadratic equation all of whose coefficients are nonzero is called complete.

A quadratic equation in which at least one of the coefficients other than the leading one (either the second coefficient or the constant term) equals zero is called incomplete.

A quadratic equation is solvable in radicals, that is, its roots can be expressed in terms of the coefficients in a general form.

Historical background on quadratic equations

Ancient Babylon

As early as the second millennium BC, the Babylonians knew how to solve quadratic equations . Solving them in Ancient Babylon was closely tied to practical problems, mainly such as measuring the area of plots of land and earthworks connected with military needs; this knowledge was also a result of the development of mathematics and astronomy in general. Methods were known for solving both complete and incomplete quadratic equations. Here are examples of quadratic equations solved in Ancient Babylon, written in modern algebraic notation:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

The rules for solving quadratic equations are in many respects similar to modern ones, but the Babylonian texts do not record the reasoning by which these rules were obtained.

India

Problems solved with the help of quadratic equations appear in the astronomical treatise "Aryabhatiya," written by the Indian astronomer and mathematician Aryabhata in 499 AD. One of the first known derivations of the formula for the roots of a quadratic equation belongs to the Indian scholar Brahmagupta (around 598) ; Brahmagupta set out a universal rule for solving a quadratic equation reduced to the canonical form: Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem; it was assumed that in it all coefficients except Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem may be negative. The rule formulated by the scholar essentially coincides with the modern one.

Roots of a quadratic equation over the real numbers

Method I. The general formula for computing roots

To find the roots of the quadratic equation Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem in the general case, one should use the algorithm below:

Compute the value of the discriminant of the quadratic equation: this is the name given to the expression Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.
Condition Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem
Number of real roots two roots one root (in some contexts one also speaks of two equal or coinciding roots — it is also called a root of multiplicity 2) we conclude that there are no roots over the real numbers.
Formula

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem


Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

for the formula of complex roots, see the corresponding section below
Derivation of the formula

The formula can be obtained as follows:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

We multiply each side by Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem and add Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Note: it is clear that the formula for a root of multiplicity 2 is a special case of the general formula, obtained by substituting D=0 into it, and the conclusion that there are no real roots when D<0 should likewise be drawn by taking into account that in this case -D>0, and Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.

The method presented is universal, but it is far from the only one.

Method II. Roots of a quadratic equation with an even coefficient b

For equations of the form Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, that is, with an even Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, where

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

simpler expressions can be used to find the roots instead of formula (1) .

Note: the formulas given below can be obtained by substituting the expression b=2k into the standard formulas and carrying out some simple transformations.

Discriminant

Roots

non-reduced reduced D>0 non-reduced reduced
it is more convenient to compute the value of

a quarter of the discriminant:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

All the necessary properties are preserved.

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem. Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem
D=0 Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Method III. Solving incomplete quadratic equations

Incomplete quadratic equations should be approached in a special way. Let us consider three possible situations.

b=0, c=0

b=0; c≠0

b≠0; c=0

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

(the transformation process is deliberately shown in detail; in practice one can go straight to the last equality)

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

If Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, then the equation has two real roots, and if Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, then the equation has no real roots.

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem or Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Such an equation always has two real roots

Method IV. Using special relationships between the coefficients

There are special cases of quadratic equations in which the coefficients are related to one another in ways that allow them to be solved much more easily.

Roots of a quadratic equation in which the sum of the leading coefficient and the constant term equals the second coefficient

If in the quadratic equation Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem the sum of the first coefficient and the constant term equals the second coefficient: Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, then its roots are Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem and the number opposite to the ratio of the constant term to the leading coefficient (Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem).

Proof

Way 1. First let us find out whether such an equation really has two roots (including two coinciding ones):

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.

Yes, it does, because for any real values of the coefficients Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, and hence the discriminant is nonnegative. Thus, if Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, the equation has two roots, while if Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, it has only one root. Let us find these roots:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

In particular, if Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, there will be one root: Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Way 2.
Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem
Geometric interpretation: the parabola given analytically by the indicated formula crosses the x-axis at two points, whose abscissas are the roots, at least one of which equals -1

We use the geometric model of the roots of a quadratic equation: we will regard them as the points of intersection of the parabola Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem with the x-axis. Every parabola, regardless of the expression defining it, is a figure symmetric about the line Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem. This means that the segment of any line perpendicular to it that is cut off by the parabola is bisected by the axis of symmetry. This holds, in particular, for the x-axis as well. Thus, for every parabola one of the following equalities holds: Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem (if Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem) or Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem (if the inequality of the opposite sense holds). Using the identity Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, which expresses the geometric meaning of the absolute value, and also assuming that Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem (this can be proved by substituting the equality into the quadratic trinomial: Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, so -1 is a root of such an equation), we arrive at the following equality: Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem Taking into account that the difference is always positive when we add the absolute value and negative when we subtract it, which shows that these cases are equivalent, and, moreover, recalling the equality Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, we remove the absolute value: Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem. In the second case, carrying out similar transformations, we arrive at the same result, Q.E.D.

Hence, before solving any quadratic equation, one should check whether this theorem can be applied to it: compare the sum of the leading coefficient and the constant term with the second coefficient.

Roots of a quadratic equation whose coefficients sum to zero

If in a quadratic equation the sum of all its coefficients equals zero (Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem), then the roots of such an equation are Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem and the ratio of the constant term to the leading coefficient (Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem).

Proof

Way 1. First of all, note that the equality Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem implies that Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem Let us determine the number of roots:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

For any values of the coefficients the equation has at least one root: indeed, for any values of the coefficients Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, and hence the discriminant is nonnegative. Note that if Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, the equation has two roots, while if Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, it has only one. Let us find these roots:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

which is what was to be proved.

In particular, if Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, the equation has only one root, which is the number Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.

Way 2. Using the definition of a root of a quadratic equation given above, we find by substitution that the number 1 is a root in the case under consideration: Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem is a true equality, so one is a root of equations of this kind. Next, by Vieta's theorem we find the second root: according to this theorem, the product of the roots of the equation equals the ratio of the constant term to the leading coefficient, Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, Q.E.D.

Hence, before solving an equation by standard methods, one should check whether this theorem applies to it: add up all the coefficients of the given equation and see whether this sum equals zero.

Method V. Factoring a quadratic trinomial into linear factors

If a trinomial of the form Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem can somehow be represented as a product of linear factors Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, then the roots of the equation Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem can be found: they will be Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem and Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem; indeed, Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, and by solving the indicated linear equations we obtain the above. Note that a quadratic trinomial cannot always be factored into linear factors with real coefficients: this is possible if the corresponding equation has real roots.

Let us consider some special cases.

Using the formula for the square of a sum (difference)

If a quadratic trinomial has the form Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, then by applying the named formula to it, we can factor it into linear factors and, therefore, find the roots:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Completing the square of a sum (difference)

The same formula is also applied through the method called "completing the square" (of a sum or difference). For a reduced quadratic equation with the notation introduced earlier, this means the following:

  1. add and subtract the same number
    Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.
  2. apply the formula to the resulting expression, and move the subtracted term and the constant term to the right-hand side
    Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem
    Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem
  3. take the square root of the left and right sides of the equation and express the variable
    Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem
    Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Note: as you may have noticed, this formula coincides with the one given in the section "Roots of the reduced quadratic equation," which, in turn, can be obtained from the general formula (1) by substituting the equality a=1. This is not just a coincidence: by the method described, with some additional reasoning, one can also derive the general formula and prove the properties of the discriminant.

Method VI. Using Vieta's theorem and its converse

Vieta's theorem (see the section of the same name below) and its converse allow reduced quadratic equations to be solved mentally, without resorting to computation by formula (1).

According to the converse theorem, any pair of numbers (or single number) Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, being a solution of the system of equations

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

are the roots of the equation Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.

The direct theorem helps in finding, mentally, numbers that satisfy these equations. With its help one can determine the signs of the roots without knowing the roots themselves. To do so, follow this rule:

1) if the constant term is negative, the roots have different signs, and the root with the larger absolute value has the sign opposite to that of the second coefficient of the equation;

2) if the constant term is positive, both roots have the same sign, and it is the sign opposite to that of the second coefficient.

Method VII. The "transfer" method

The so-called "transfer" method makes it possible to reduce the solution of non-reduced equations, which cannot be converted to reduced form with integer coefficients by dividing by the leading coefficient, to the solution of reduced equations with integer coefficients. It consists of the following:

1) multiply both sides by the expression:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

2) introduce a new variable Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Next, the equation is solved mentally in the way described above, then one returns to the original variable and finds the roots of the equations Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem and Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.

Example

Suppose we want to solve the equation Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem using the converse of Vieta's theorem. If we try to divide both sides by 8, we obtain a reduced equation with fractional coefficients, so it will be hard to apply the theorem to it. However, by using the transfer method, we can obtain a reduced equation with integer coefficients:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.

Making the change of variable y=8x, we arrive at the equation:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.

Clearly, its roots are the numbers -4 and 2. We now perform the reverse substitution:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Geometric meaning

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

The graph of a quadratic function is a parabola. The solutions (roots) of a quadratic equation are the abscissas of the points where the parabola crosses the x-axis. If the parabola described by the quadratic function does not intersect the x-axis, the equation has no real roots. If the parabola meets the x-axis at one point (the vertex of the parabola), the equation has one real root (one also says that the equation has two coinciding roots). If the parabola crosses the x-axis at two points, the equation has two real roots (see the image on the right.)

If the coefficient Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem is positive, the branches of the parabola point upward, and vice versa. If the coefficient Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem is positive (for positive Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem; for negative, the opposite), then the vertex of the parabola lies in the left half-plane, and vice versa.

Graphical method of solving quadratic equations

Besides the universal method described above, there is the so-called graphical method. In general, this method of solving a rational equation of the form Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem consists of the following: the graphs of the functions Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem and Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem are plotted in one coordinate system, and the abscissas of the common points of these graphs are found; the numbers found are the roots of the equation.

There are only five main ways to solve quadratic equations graphically.

Way I

To solve the quadratic equation Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem by this method, the graph of the function Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem is plotted and the abscissas of the points where this graph meets the Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem-axis are found.

Way II

To solve the same equation by this method, it is transformed to the form Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem and the graphs of the quadratic function Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem and the linear function Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem are plotted in one coordinate system, and then the abscissas of their intersection points are found.

Way III

Solving by this method involves transforming the original equation to the form Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem using the method of completing the square (of a sum or difference), and then to Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem. After that, the graph of the function Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem is plotted (it is the graph of the function Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem shifted by Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem scale units to the right or to the left, depending on the sign), together with the line Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, parallel to the x-axis. The roots of the equation are the abscissas of the points where the parabola and the line intersect.

Way IV

The quadratic equation is transformed to the form Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, the graph of the function Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem is plotted (it is the graph of the function Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem shifted by Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem scale units upward if this coefficient is positive, or downward if it is negative), along with Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, and the abscissas of their common points are found.

Way V

The quadratic equation is transformed to a special form:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

then

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.

After performing the transformations, the graphs of the linear function Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem and the inverse proportionality Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem are plotted, and the abscissas of the intersection points of these graphs are found. This method has a limit of applicability: if Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, the method is not used.

Solving quadratic equations with a compass and straightedge

The graphical methods described above have significant drawbacks: they are quite laborious, and the accuracy of constructing the curves, parabolas and hyperbolas, is low. These problems do not affect the method proposed below, which relies on relatively more accurate constructions with a compass and straightedge.

To carry out such a solution, the following sequence of steps must be performed.

  1. Construct in the coordinate system Oxy a circle with its center at the point Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, passing through the point C(0;1) on the y-axis.
  2. Then three cases are possible:
    • the length of the circle's radius exceeds the length of the perpendicular dropped from the point S to the x-axis: in this case the circle crosses the x-axis at two points, and the equation has two real roots equal to the abscissas of these points;
    • the radius equals the perpendicular: one point and one real root of multiplicity 2;
    • the radius is less than the perpendicular: there are no roots in the set Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.

Roots of a quadratic equation over the complex numbers

An equation with real coefficients

A quadratic equation with real coefficients Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem has exactly two complex roots, as the fundamental theorem of algebra states. Depending on the value of the discriminant Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, either one or both roots may have no imaginary part and be real:

  • for Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem there are two real roots, and they are computed by the formula

    Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

  • for Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem there is one root (which can also be described as two equal or coinciding roots), of multiplicity 2:

    Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

  • for Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem there are no real roots, but there are two complex roots, expressed by the same formula as for a positive discriminant. It can also be rewritten by expressing the square root of a negative number as the product of a root and the imaginary unit:

    Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Equation with complex coefficients

In the complex case, a quadratic equation is solved by the same formula (1) and its variants given above, but only two cases can be distinguished: a zero discriminant (one double root) and a nonzero discriminant (two simple roots).

Roots of the reduced quadratic equation

A quadratic equation of the form Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem in which the leading coefficient Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem equals one is called reduced (or monic). In this case the formula for the roots (1) simplifies to

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Mnemonic rules:

  • From the "Radionyanya" radio show:

Write a "minus" first,
Next to it p halved,
"Plus-minus" the radical sign,
Familiar to us since childhood.
And under the root, my friend,
It all comes down to a trifle:
p halved and squared
Minus the lovely q.

  • From "Radionyanya" (another version):

p, taken with the opposite sign,
We will divide by two,
And from the root, carefully,
We will separate it with a "minus-plus" sign.
And under the root, quite conveniently,
Half of p squared
Minus q — and there are the solutions,
That is, the roots of the equation.

Vieta's theorem

Statement

The sum of the roots of the reduced quadratic equation Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem is equal to the coefficient Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem taken with a minus sign, and the product of the roots is equal to the constant term Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

In the general case, that is, for a non-reduced quadratic equation Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Using this theorem, some quadratic equations can be solved mentally.

Example

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Factoring a quadratic trinomial and the theorems that follow from it

If both roots of a quadratic trinomial are known, it can be factored using the formula

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem (2)

Proof

To prove this statement, we use Vieta's theorem. According to this theorem, the roots Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem and Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem of the quadratic equation Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem satisfy the following relations with its coefficients: Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem. Let us substitute these relations into the quadratic trinomial:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.

In the case of a zero discriminant, this relation becomes one of the forms of the square of a sum or difference formula.

Two important corollaries follow from formula (2):

Corollary 1

If a quadratic trinomial factors into linear factors with real coefficients, then it has real roots.

Proof

Let Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem. Then, rewriting this factorization, we obtain:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.

Comparing the resulting expression with formula (2), we find that the roots of such a trinomial are Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem and Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem. Since the coefficients are real, the numbers opposite to their ratios are also elements of the set Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.

Corollary 2

If a quadratic trinomial has no real roots, then it does not factor into linear factors with real coefficients.

Proof

Indeed, if we assume the contrary (that such a trinomial factors into linear factors), then, by Corollary 1, it has roots in the set Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, which contradicts the hypothesis; therefore our assumption is false, and such a trinomial does not factor into linear factors.

Equations reducible to quadratic equations

Algebraic

An equation of the form Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem is an equation reducible to a quadratic one.

In the general case it is solved by the substitution Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem followed by solving the quadratic equation Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem.

It is also possible to solve it without a substitution, by solving a system (union) of two equations:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem and

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

If Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, then the equation takes the form:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Such an equation is called biquadratic .

By means of the substitution

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

the following equation is reduced to a quadratic equation

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

known as a reciprocal (or generalized symmetric) equation .

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

For the quadratic function:
f (x) = x2 − x − 2 = (x + 1)(x − 2) of a real variable x, the x-coordinates of the points where the graph crosses the x-axis, x = −1 and x = 2, are the solutions of the quadratic equation: x2 − x − 2 = 0.

Differential

A second-order linear homogeneous differential equation with constant coefficients

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

is reduced by the substitution Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem to the characteristic quadratic equation:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

If the solutions of this equation Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem and Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem are not equal to each other, then the general solution has the form:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, where Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem and Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem are arbitrary constants.

For complex roots Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem the general solution can be rewritten using Euler's formula:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

If the solutions of the characteristic equation coincide, Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem, the general solution is written in the form:

Quadratic Equation ax² + bx + c = 0 (a ≠ 0) and Vietas Theorem

Equations of this type often occur in a wide variety of problems in mathematics and physics, for example, in the theory of oscillations or the theory of alternating current circuits.

Applications of solving quadratic equations

Solving quadratic equations has many practical applications in various fields. Here are some of the main ones:

1. Physics and mechanics

  • Trajectory calculation: The formulas for the motion of objects thrown at an angle or of freely falling bodies often involve quadratic equations for calculating trajectories, velocity and time.
  • Acceleration and deceleration: When analyzing motion with acceleration or deceleration, quadratic equations help calculate the distance a body travels in a given time.

2. Construction and architecture

  • Space optimization: When designing rooms, architects use quadratic equations to calculate optimal dimensions and load distribution.
  • Forces and stability: Equations with quadratic dependence are used to calculate the forces on beams, arches and other structural elements, especially in bridge and building projects.

3. Economics and business

  • Profit maximization and cost minimization: In economics, quadratic equations are used to analyze profitability and optimize costs, for example, to determine the points of maximum or minimum profit.
  • Supply and demand analysis: Quadratic equations can also be used to find equilibrium points and analyze trends.

4. Engineering and technology

  • Electric circuits and oscillations: In electrical engineering, quadratic equations are used to calculate the amplitude and frequency of oscillations, especially in circuits with inductance and capacitance.
  • Optics and focusing: Quadratic equations are important for calculating focal length in optics, in order to ensure an accurate image.

5. Financial modeling

  • Loan and mortgage calculation: When calculating loan and mortgage payments, quadratic equations are used to determine optimal payment amounts and the total interest.
  • Investment calculations: In problems of estimating investment growth and analyzing returns, quadratic dependencies are also used to predict changes.

6. Computer graphics and animation

  • 3D modeling and rendering: Quadratic equations are used to model curved surfaces, shadows and lighting.
  • Physics in games: When creating simulations of object motion, such as a ball bouncing at different angles, or projectile trajectories, quadratic equations help calculate realistic motion and collisions.

7. Astronomy and space exploration

  • Orbit calculations: Quadratic equations are used to determine the trajectories of space objects, calculate satellite orbits and predict the motion of planets.
  • Mass and gravity calculations: These equations are important for computing gravitational forces and the velocities of celestial bodies.

8. Solving differential equations

  • Characteristic equation: When solving linear differential equations with constant coefficients, a characteristic equation is often formed, which may be quadratic. For example, for equations of the form ay′′+by′+cy=0 the characteristic equation ar2+br+c=0 is quadratic. The roots of this equation give the solution of the differential equation.
  • Oscillatory systems: In problems of mechanics and electrical engineering that involve oscillatory processes (for example, in an oscillating circuit or in systems with springs), quadratic equations help determine the frequency and amplitude of oscillations. Second-order differential equations describing oscillations often lead to quadratic characteristic equations, and solving them yields the oscillation frequency.

These examples show that quadratic equations are essential for analyzing and solving problems in science, engineering, business and other practical fields where a quadratic dependence is present.

See also

  • [[b3231]]
  • [[b3604]]
  • [[b3542]]
  • [[b3540]]
  • Solving quadratic equations with continued fractions
  • Linear equation
  • Cubic function
  • Quartic equation
  • Fundamental theorem of algebra
  • Quintic equation

See also

created: 2014-10-05
updated: 2026-09-29
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