This circuit shows a current source. The current through the load is the same regardless of the switch position. The op-amp tries to keep the same voltages at both terminals, so V- = V+. Call V1 the voltage across R1, and I1 the current through R1. Then V2 = V4. Since I1 = I2 and R1 = R2, V1 = V2 = V4. V- = V+ = V1 - 5V I3 = V+/R3 = (V1 - 5V)/R3. I4 = I3 + I load. I4 = V4 / R4 = V1 / R3. V1 / R3 = (V1 - 5 V) / R3 + I load I load = 5 V / R3 = 1.67 mA
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